Distributivity: Difference between revisions
(Created page with "== Formal definition == A predicate <math>P(\mathbf x)</math> is '''distributive''' in terms of its argument <math>\mathbf x</math> iff : <math>\forall \mathbf x. P(\mathbf x)...") |
(forcing (non)distributivity) |
||
| (One intermediate revision by one other user not shown) | |||
| Line 1: | Line 1: | ||
In [[plural logic]], a predicate <math>P</math> is '''distributive''' over its argument <math>xx</math> if and only if these two statements are equivalent: | |||
: | |||
# <math>P(xx)</math>. | |||
# For all <math>x</math> among <math>xx</math>, <math>P(x)</math>. | |||
For example, <math>\textsf{dua}(x, y)</math> ''distributes'' over both its arguments since if all of a group of people know several things, this means that each of them knows each of those things. Meanwhile, <math>\textsf{gu}(x)</math> is non-distributive because each of two things are not themselves two. | |||
== Being explicit == | |||
=== Forcing distributivity === | |||
If you have a non-distributive verb like {{t|hao}}, how do you distribute it over some plural constant? | |||
One way is to use the word {{t|shıcha}} “▯ satisfy property ▯ individually/one by one,” in a [[serial verb]]. | |||
{{example|Shıcha hao náq.|The guys <i>hao</i> one by one.}} | |||
Another is to use {{t|tú mea X}} “each among X”. | |||
{{example|Hao tú mea náq.|Each of the guys <i>hao</i>s.}} | |||
=== Forcing non-distributivity === | |||
If you have a distributive verb like {{t|geı}}, how do you apply it to a plural subject without getting a distributive meaning? | |||
{{example|😕 {{red|Geı}} ké deo gu tíefuq.|The two children {{red|(each) wear}} the coat.<br><small>Both D₁ wears T and D₂ wears T — nonsense.</small>}} | |||
One way is to use the word {{t|mecha}} “▯ satisfy property ▯ as a group,” in a serial verb. | |||
{{example|Mecha geı ké deo gu tíefuq.|The two children wear the coat together.<br><small>(D₁+D₂) considered as a unit wears T</small>}} | |||
Another is to use {{t|me}} “an aggregate of….” An '''aggregate''' is a plural value wrapped in a singularizing wrapper, shielding it from effects like distributivity. | |||
{{example|Geı {{green|ké me kê deo gu}} tíefuq.|{{green|The two-child-bundle}} wears the coat.<br><small>(D₁+D₂) considered as a unit wears T</small>}} | |||
Latest revision as of 16:01, 16 February 2026
In plural logic, a predicate is distributive over its argument if and only if these two statements are equivalent:
- .
- For all among , .
For example, distributes over both its arguments since if all of a group of people know several things, this means that each of them knows each of those things. Meanwhile, is non-distributive because each of two things are not themselves two.
Being explicit
Forcing distributivity
If you have a non-distributive verb like hao, how do you distribute it over some plural constant?
One way is to use the word shıcha “▯ satisfy property ▯ individually/one by one,” in a serial verb.
Shıcha hao náq.
The guys hao one by one.
Another is to use tú mea X “each among X”.
Hao tú mea náq.
Each of the guys haos.
Forcing non-distributivity
If you have a distributive verb like geı, how do you apply it to a plural subject without getting a distributive meaning?
😕 Geı ké deo gu tíefuq.
The two children (each) wear the coat.
Both D₁ wears T and D₂ wears T — nonsense.
One way is to use the word mecha “▯ satisfy property ▯ as a group,” in a serial verb.
Mecha geı ké deo gu tíefuq.
The two children wear the coat together.
(D₁+D₂) considered as a unit wears T
Another is to use me “an aggregate of….” An aggregate is a plural value wrapped in a singularizing wrapper, shielding it from effects like distributivity.
Geı ké me kê deo gu tíefuq.
The two-child-bundle wears the coat.
(D₁+D₂) considered as a unit wears T